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发表于 2014-6-2 17:03:11
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本帖最后由 meigen 于 2014-10-10 20:19 编辑 / q" Z) k! D% R! P1 |
2 l, r! a/ P% V7 t接14楼，单色图的提取稍微麻烦些，他里面只有数据部分而缺少文件头，这个是比较头疼的事情
( a4 [! r" H7 U {- d/ G7 }先用ebdump提取出词典文本（本文），然后在里面获取单色图的代码(<1F44>开头，<1F64>结尾)
( Z0 L& \; G+ u5 G* i: o可以看到
- O0 e& E* J" T" g: Q& g6 _9 G<1F44><0001><w=200,h=256>xxx<1F64>[0001A4BD:0027]0 ]" d1 o5 I# K9 {
这里的w=200,h=256表示图片的尺寸，这个参数后面会用到1 C8 q+ G) T0 Q$ l+ ]
然后<1F64>后面的这一段[0001A4BD:0027]就是单色图数据地址了3 C& {+ O# |9 N) B3 W- u
先写个Demo 把所有地址都提取出来，顺便排一下序，去掉重复:% I& n8 u! T! ?( Z4 ?) Z
- static void getMonoTag(String f) {$ A) t' F! D" C) T! o% k- |
- try {" P; o6 f9 o! ~4 P9 ?5 E
- BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(f+".txt"), "Shift_JIS"));& {- S( x( [1 ~6 v! j+ C
- BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(f+".mono.txt"), "UTF-8"));& ^$ e. B; W, ?1 C {
- String line;: u# V) Q. B( i0 g1 I
- ArrayList<String> monos = new ArrayList<String>();, o7 j8 I+ b# [- F) Z; m; T
- while (((line = reader.readLine()) != null)) {
. Y- t4 N# ~, [& s - while (line.contains("<1F64>")) {5 {' X; Q' a) m( x c. p& b
- line = line.substring(line.indexOf("<1F64>") + 6);
( T# f6 ` s4 {5 S1 P; } - monos.add(line.substring(0, 15));
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- }7 p' `; P( E) l. Y: z- B. C% D
- reader.close();6 a; H' |/ `# `& F9 j) I
- String[] monoa = new String[monos.size()];
: v3 i, k _) C! y1 ~ - monos.toArray(monoa);7 F4 K) y. K0 t4 X' u' |+ a
- Arrays.sort(monoa);# m0 |% z1 ~, A B
- String last = "";
8 G% o4 R" V3 L: _$ L$ t& q. { - for (int i=0; i<monoa.length; i++) {- K) z$ d# D. z
- if (!monoa[i].equals(last)), G# [- B" W# t9 ^
- writer.write(monoa[i] + "\r\n");
8 y" ^5 v# d: }. R$ k0 {! Z - last = monoa[i];; R( k% A& p2 ]2 i
- }8 `. n! }$ r9 a) l5 C8 k
- writer.close();
# C; @7 b1 \/ Q* }; f - } catch (Exception e) {! I f6 V; M8 t! K, E
- e.printStackTrace();
. a2 c# p; m$ m* Y6 r! T - }
9 e% L7 B# ]# t- B/ N; C7 C% ~& [ - }
得到了一个.mono.txt的文件
5 v: {* l' H) V; j# x: M4 J然后开始提取:6 ^' {8 h, s& S% x/ h
上面有提到w=200,h=256这两个参数，不过epwing好像弄反了，200是高，256是宽。 - -: B! Z3 Y' W( | q1 v5 J
提取过程中需要手动加上图像的文件头，可自行百度bmp文件格式+ @ @% T n; [7 n2 o2 `
- static final int WIDTH = 256;
# {0 `7 H' @0 k+ h" t - static final int HEIGHT = 200;6 y% C1 i. ]( t& H
- static final int WIDTH2 = 32;
+ S$ o( J( a/ X! w, l4 q - static final int SIZE = WIDTH2 * HEIGHT;6 q: t/ d" i2 ~% f0 i! x
- static final int FILE_LEN = SIZE + 62;5 l& P, J8 C, q" r4 ^6 E% @9 E
- static byte[] filehead = {0x42, 0x4d,' @* _" q" J. e( O2 ^* x
- (byte) (FILE_LEN & 0xff), (byte) ((FILE_LEN >> 8) & 0xff), (byte) ((FILE_LEN >> 16) & 0xff), (byte) ((FILE_LEN >> 24) & 0xff),
2 I% \& k5 p. ~! A - 0, 0, 0, 0, 0x3e, 0, 0, 0};
4 T \0 ^' Z p2 W* E/ V6 I* s - static byte[] infohead = {0x28, 0, 0, 0,. s- L* M, x% b5 M$ N7 D# M6 L* d
- (byte) (WIDTH & 0xff), (byte) ((WIDTH >> 8) & 0xff), (byte) ((WIDTH >> 16) & 0xff), (byte) ((WIDTH >> 24) & 0xff),+ f9 U! Y, m9 Q* e6 k
- (byte) (HEIGHT & 0xff), (byte) ((HEIGHT >> 8) & 0xff), (byte) ((HEIGHT >> 16) & 0xff), (byte) ((HEIGHT >> 24) & 0xff),
: n$ x" r4 D) E6 w, v" l - 1, 0, 1, 0, 0, 0, 0, 0,
/ b' J" L2 X2 c4 f - (byte) (SIZE & 0xff), (byte) ((SIZE >> 8) & 0xff), (byte) ((SIZE >> 16) & 0xff), (byte) ((SIZE >> 24) & 0xff),& u1 |& L' m, Z( m. Z6 A
- 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 2, 0, 0, 0, -1, -1, -1, 0, 0, 0, 0, 0};
) Y! e: \) c( K$ |9 ` - static void getMonoPic(String f, String m) {; C+ F" P, D5 o, \
- try {! G) c( E0 T4 E; ^
- BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(f+".txt"), "Shift_JIS"));
" r. i3 v& n; R9 v; Z" o% g - BufferedReader reader2 = new BufferedReader(new InputStreamReader(new FileInputStream(m+".txt"), "UTF-8"));" U& I7 _( M: M: m# A1 w% ~6 Q
- OutputStream out = null;9 @2 w; |2 s2 o
- String line = "";
) E! e9 W1 [! h$ v% ?( A' Q - String line2 = reader2.readLine();1 I% N' l% T/ V- G# R7 V6 E
- int block = 0;+ o- X' m! G: ?7 @0 L- z8 y/ |& c' y
- int block2 = Integer.parseInt(line2.substring(1, 9), 16);3 o0 G- O3 i3 x ^! O9 y6 t
- int offs = Integer.parseInt(line2.substring(10, 14), 16);
. |) V4 U0 u1 W* O( r/ Y - byte[] temp = new byte[2048];( @- Q& x& }' w7 j1 [8 X
- byte[] data = new byte[WIDTH2 * HEIGHT];$ v7 B8 z4 X8 @" c. @
- int[] idxs = new int[WIDTH2 * HEIGHT];
0 `* P' G8 X# T4 B - for (int i=0; i<HEIGHT; i++) {4 `$ l7 P& a1 T& z
- idxs[i * WIDTH2] = (HEIGHT - 1 - i) * WIDTH2;) v7 K4 N2 c; k! B3 ]) _) L
- for (int j=1; j<WIDTH2; j++)
3 @" n9 _6 I5 p. `0 q - idxs[i * WIDTH2 + j] = idxs[i * WIDTH2 + j - 1] + 1;5 L# L5 K* H+ q( _; w2 A
- }
) n( s3 S( |& {. ]+ f; d - int idx = 0;
$ `4 x0 I' ^: h. a% {7 L - int didx = 0;# f$ C. @3 U. |2 u
- while (((line = reader.readLine()) != null)) {7 R- i+ J& N4 b( Q. n6 y+ ]
- if(line.startsWith("block")) {
1 k: F5 t7 o% r; ? - block = Integer.parseInt(line.substring(6, 11), 16);
" B' ] C# P+ n- w% n - idx = 0;
* @' L; p. S* [- d9 c x. s) Y# x - }
+ [# i8 I: D) Y) | - if(line.startsWith("0")) {
. W8 N2 d& E: n' ~3 d/ `7 A ]" ^) R - for(int i=0; i<16; i++) {
. h& ^3 w- q" q% V$ f8 _5 j) j$ h - int a = CHARS.indexOf(line.charAt(5+3*i));
1 s/ _. [1 G% S/ f7 r" { - int b = CHARS.indexOf(line.charAt(6+3*i));& \* d# Q5 L/ X: z5 e
- temp[idx++] = (byte) (a << 4 | b);
* u2 W/ @ S* E/ Z - }
* T# y, t% r7 M3 C0 n0 G" t9 Q& F - }# p3 G' y8 z" o
- if (idx == 2048) {
7 ~; a4 k8 ^) K0 R - if(block < block2) continue;( F' G& |" L+ X! d3 x
- int start = offs;
" b* O1 v# v/ Q/ @' M! U, e - if(didx != 0) start = 0;
3 Y8 n1 A* |, C) R! f) g - for(int i=0; i<2048; i++) {
; }- c$ U8 r) l0 l$ r0 A" U - if(i >= start)/ ^7 ]# F4 k% y; a! b0 H% u
- data[idxs[didx++]] = temp[i];1 { ?: Q4 w# h k u+ ` l
- if(didx == WIDTH2 * HEIGHT) {$ U- S4 \0 Q* V5 ]& H* p/ H* ~
- System.out.println(toHex(block2)+"."+toHex(offs));
" T4 \9 R* T1 t, I1 v4 e/ a/ _9 E - out = new BufferedOutputStream(new FileOutputStream("pic/"+toHex(block2)+toHex(offs)+".bmp"));3 |6 B7 e9 m3 _" @. r+ I* e7 Z& c- G
- out.write(filehead);
8 k$ f3 L% Q- Q# I X1 u) f& S6 y - out.write(infohead); C: \- } y$ h( A1 F6 z0 b' \
- out.write(data);
& `& g3 t* }& {; ^ d$ n: ? - out.flush();6 j, ~) C* G* o5 K X4 L3 |
- out.close();
[3 U J7 G) Z/ G$ h8 ?7 ~ - line2 = reader2.readLine();! r) S7 s6 d! ^2 M
- if(line2 == null || line2.equals("")) {3 D: G% s$ a) i, U( L) r( a
- reader.close();
3 }' d+ T& e1 C! _/ ~% L - reader2.close();
% R: L* g/ L: ?! p - return;) s0 v# w- Z0 o6 C f
- }
; s1 B4 U; J( T- r5 M6 B% a - block2 = Integer.parseInt(line2.substring(1, 9), 16);( f* C7 |) T" x7 y+ s( [* s% ]& t' C
- offs = Integer.parseInt(line2.substring(10, 14), 16);( i6 _. X* M4 x4 ?1 m; n2 X( _
- didx = 0;
& l1 e8 t* s$ }; v+ b0 } - }
& `. f; q* W9 G' H6 j H7 W8 ~ x - }% S8 F; s& J. M0 o: }" h5 P6 z
- idx = 0;
& ?$ D _; _$ Z - }# ~. Q0 F+ D D6 I
- }
& V! r- F; f) M7 K; v0 @# Y - reader.close();' Q8 u! c4 ?! e0 d
- reader2.close();" [( c g$ |, w3 X& G
- } catch (Exception e) {/ C" r1 e/ k' t4 `2 K& l
- e.printStackTrace();
5 _4 x+ l7 S5 k4 m' `8 `+ H - }
, t1 I/ M, P5 B6 ?0 Z- B+ ^- q/ f - }
待编辑..." z. N. X7 g( U7 b. {2 r
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回15楼:
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代码有一些要改动的地方, 我完善一下就传附件
& _5 P8 h$ x* ~" w# a另外用英文说明这...{:11_336:} $ z, C" S. l" G6 z
我先用中文注释一下, 然后再慢慢翻译 |
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发表于 2013-11-11 10:58:55
