正则表达式求助

2011star21cn

<div class="C2_word_form"><span><span class="C2_inline_word">takes</span>, <span class="C2_inline_word">taking</span>, <span class="C2_inline_word">took</span>, <span class="C2_inline_word">taken</span></span></div>
<span class="C2_inline_word">taken</span>

能否实现把<div class="C2_word_form">...</div>标签内的 C2_inline_word 替换掉
而<div class="C2_word_form">...</div>标签外的不变
/ D, k# @% T" ~( g" }即变成如下：
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. m+ Q3 E& ~) C4 {8 G* n<div class="C2_word_form"><span><span class="C2_word_form_word">takes</span>, <span class="C2_word_form_word">taking</span>, <span class="C2_word_form_word">took</span>, <span class="C2_word_form_word">taken</span></span></div>
<span class="C2_inline_word">taken</span>

Oeasy

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1. <div class="C2_word_form">(.+?)C2_inline_word(.+?)</div>

复制代码

# |- M* s: r0 c9 F: S, r" ^4 Y替换为
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1. <div class="C2_word_form">\1C2_word_form_word\2</div>

复制代码

; o: H* c% v9 n- E. \点击“Replace All”（替换全部） n 次，直到替换结果为 0 为止。
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2011star21cn

谢谢O大
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不过这个式子没有能达到结果

$ t" ^; S* \. k5 ~( H1 T替换多次后会把<div class="C2_word_form">...</div>外面的C2_inline_word也替换掉
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初始代码
<div class="C2_word_form"><span>also <span class="C2_inline_word">twenty-four seven</span></span></div><div class="C2_explanation_box"><span class="C2_explanation_label">[ADV: ADV after v]</span><span class="C2_explanation_content">If something happens <span class="C2_inline_word">24-7</span>, it happens all the time without ever stopping. <span class="C2_inline_word">24-7</span> means twenty-four hours a day, seven days a week.<span class="C2_ex_label_end">[mainly AM, INFORMAL]</span></span></div>
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替换后代码
<div class="C2_word_form"><span>also <span class="C2_word_form_word">twenty-four seven</span></span></div><div class="C2_explanation_box"><span class="C2_explanation_label">[ADV: ADV after v]</span><span class="C2_explanation_content">If something happens <span class="C2_word_form_word">24-7</span>, it happens all the time without ever stopping. <span class="C2_word_form_word">24-7</span> means twenty-four hours a day, seven days a week.<span class="C2_ex_label_end">[mainly AM, INFORMAL]</span></span></div>
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期望的结果

) J3 H. k+ b# s4 O$ E+ n! h: e: R<div class="C2_word_form"><span>also <span class="C2_word_form_word">twenty-four seven</span></span></div><div class="C2_explanation_box"><span class="C2_explanation_label">[ADV: ADV after v]</span><span class="C2_explanation_content">If something happens <span class="C2_inline_word">24-7</span>, it happens all the time without ever stopping. <span class="C2_inline_word">24-7</span> means twenty-four hours a day, seven days a week.<span class="C2_ex_label_end">[mainly AM, INFORMAL]</span></span></div>

ryuya

如果你只是想要css控制div內跟外的C2_inline_word
要有不同顯示效果，那根本不需要用正則

1 l9 C5 R6 B2 t: Y.C2_inline_word {font-weight:normal;}
. f0 [5 S6 X: }! d2 Y  }* X$ z1 x1 qC2_word_form .C2_inline_word {font-weight:bold;}
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即使都是同一tag，也可以分粗細

Oeasy

2011star21cn 发表于 2016-1-10 21:22
谢谢O大
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不过这个式子没有能达到结果

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" h. V7 w; e! q& W9 b应该有能一步到位的办法，但是我好久没实战操作了，一时想不出来。
有个曲线救国的办法就是：
1. </div>后面加个换行（</div>全部替换为 </div>\r\n 额，看你用啥文本编辑器，也可能是替换为 </div>\n）
! B9 u. `, \( |- G! [9 z& S0 m: x2. 再用我楼上的替换。
3. 有必要的话，再把</div>后面的换行删除。
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2011star21cn

谢二位，今天学了好多！